$C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to$

C H_{3} - C H_{2} - C H_{2} - C H - C H_{2} - C H_{3}

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C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3}

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C H_{3} - C H_{2} - C H - C H - C H_{2} - C H_{3}

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C H_{3} - C H_{2} - C H_{2} - C H (B r) - C H_{2} - C H_{3}

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Solution

The correct option is D $C H_{3} - C H_{2} - C H_{2} - C H (B r) - C H_{2} - C H_{3}$
A molecule of $H B r$ is added to carbon carbon double bond to give alkyl bromide.
$C H_{3} - C H_{2} - C H = C H - C H_{2} - C H_{3} + H B r \to C H_{3} - C H_{2} - C H_{2} - C H (B r) - C H_{2} - C H_{3}$

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Similar questions

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H_{2} - C H | C H_{3} - C | C H_{3} - C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

A g N O_{3}

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