${C H}_{3} {C H}_{2} - C l$ undergoes homolytic fission to produce :

{C H}_{3} {˙ C H}_{2} a n d ˙ C l

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{C H}_{3} {C H}_{2} a n d {C l}^{⊖}

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{C H}_{3} {\oplus C H}_{2} a n d {C l}^{⊖}

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{C H}_{3} {\oplus C H}_{2} a n d {C l}^{\oplus}

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Solution

The correct option is A ${C H}_{3} {˙ C H}_{2} a n d ˙ C l$
Hence, the correct option is A.

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Similar questions

C H_{3} - C H_{3}, C H_{3} - C H_{2} - C H_{3}, (C H_{3})_{2} C H - C H_{3}, C H_{3} - C H_{2} - C H (C H_{3})_{2} .

C H_{3} - C H_{3}, C H_{3} - C H_{2} - C H_{3}, (C H_{3})_{2} C H - C H_{3}, C H_{3} - C H_{2} - C H (C H_{3})_{2} .

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

S_{N} 2

c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

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