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Question

CH3CH2Clalc.KOH−−−−A. the product is

A
CH3CH2OK
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B
CH3CHO
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C
CH3CH2OCH3CH3
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D
CH2=CH2
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Solution

The correct option is D CH2=CH2
The addition of KOH to alkyl halides results in the formation of alkene, which in this case, is Ethene.

CH3CH2Clalc.KOH−−−−CH2=CH2

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