CH3 - CH2 - OH CH2 - CH2 - Cl - X - HCl 3CH3 - CH2 - OH CH3 - CH2 - Cl - YHybridisation of central atoms present in X - Y are respectively

The correct option is A sp, sp^3 CH_3 CH_2 OHCOCl_2→ CH_3 CH_2 Cl+CO_2+HCl 3CH_3 CH_2 OHPCl_3→ CH_3 CH_2 Cl + H_3PO_3 For CO_2 , central at ...

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Standard XII

Chemistry

Bond Length

CH3 - CH2 - O...

Question

$C H_{3} - C H_{2} - O H + C O C l_{2} - ---- \to P y r i d e n e C H_{2} - C H_{2} - C l + X + H C l$
$3 C H_{3} - C H_{2} - O H + P C l_{3} - --- \to C H_{3} - C H_{2} - C l + Y$
Hybridisation of central atoms present in $X & Y$ are respectively

s p, s p^{3}

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s p^{3}, s p^{2}

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s p^{2}, s p^{3}

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s p^{4}, s p^{2}

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Solution

The correct option is A $s p, s p^{3}$
$C H_{3} - C H_{2} - O H C O C l_{2} \to C H_{3} - C H_{2} - C l + C O_{2} + H C l$
$3 C H_{3} - C H_{2} - O H P C l_{3} \to C H_{3} - C H_{2} - C l + H_{3} P O_{3}$
For $C O_{2}$ , central atom $C$ is $s p$ hybridised whereas for $H_{3} P O_{3}$ , central atom $P$ is $s p^{3}$ hybridised.
Thus, the correct answer is $s p, s p^{3}$

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CH3−CH2−OH+COCl2−−−−−→PyrideneCH2−CH2−Cl+X+HCl3CH3−CH2−OH+PCl3−−−−→CH3−CH2−Cl+YHybridisation of central atoms present in X&Y are respectively

The correct option is A sp,sp3CH3−CH2−OHCOCl2→CH3−CH2−Cl+CO2+HCl3CH3−CH2−OHPCl3→CH3−CH2−Cl+H3PO3For CO2, central atom C is sp hybridised whereas for H3PO3, central atom P is sp3 hybridised.Thus, the correct answer is sp, sp3

$C H_{3} - C H_{2} - O H + C O C l_{2} - ---- \to P y r i d e n e C H_{2} - C H_{2} - C l + X + H C l$
$3 C H_{3} - C H_{2} - O H + P C l_{3} - --- \to C H_{3} - C H_{2} - C l + Y$
Hybridisation of central atoms present in $X & Y$ are respectively