CH 3 - CH 2 - Cl - CH - CH 3 obtained by chlorination of n-butane- will be

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Byju's Answer

Standard XII

Chemistry

Free Radical Halogenation

CH 3 - CH 2 -...

Question

${C H}_{3} - {C H}_{2} - C H | C l - {C H}_{3}$ obtained by chlorination of n-butane, will be

l

-form

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d

-form

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meso-form

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racemic mixture

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Solution

The correct option is D racemic mixture
Chloronation of $n - b u t a n e$ take place via for radial formation i.e. $C l_{2} h r - \to C l^{.} + C l^{.}$

$C l^{-}$ may attack from either side, so, the product formed will have equal % of $l - 2 - c h l o r o b u t a n e$ & $d - 2 - c h l o r o b u t a n e$

So, the mixture will be a racemic mixture.
Hence, Option "D" is the correct answer.

Suggest Corrections

Similar questions

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(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} N H_{2}

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(1^{o})

(b)

C H_{3} - C H_{2} - N H_{2} | C H - C H_{3}

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(1^{o})

(c)

C H_{3} - C H_{3} | C H - C H_{2} - N H_{2}

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C H_{3} - C H_{3} | C | - C H_{3} N H_{2}

2-methylpropan-2-amine

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(e)

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C H_{3} - C H_{2} - \oplus C H_{2}

C H_{3} - C H | F - \oplus C H_{2}

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Arrange the following carbocations in decreasing order of their stability:

Q. Pick out the correct reactions:

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

Q. In the given compound A,C and A,D are exbhits which of the following isomerism :

(a)

C H_{3} - C H_{2} - C H_{2} - C H_{2} N H_{2}

Butanamine

(1^{o})

(b)

C H_{3} - C H_{2} - N H_{2} | C H - C H_{3}

Butan-2-amine

(1^{o})

(c)

C H_{3} - C H_{3} | C H - C H_{2} - N H_{2}

2-Methylpropanamine

(1^{o})

(d)

C H_{3} - C H_{3} | C | - C H_{3} N H_{2}

2-methylpropan-2-amine

(1^{o})

(e)

C H_{3} - C H_{2} - C H_{2} - N H - C H_{3}

N-methylpropanamine

(2^{o})

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CH3−CH2−CH|Cl−CH3 obtained by chlorination of n-butane, will be

${C H}_{3} - {C H}_{2} - C H | C l - {C H}_{3}$ obtained by chlorination of n-butane, will be