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Question

CH3CH2CONH2ACH3CH2NH2BCH3CH2OH
In the above sequence A & B respectively are :

A
Br2/KOH,NaOH
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B
Br2/KOH,HNO2
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C
KMnO4,KOH
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D
HNO2,Br2/KOH
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Solution

The correct option is A Br2/KOH,HNO2
The first reaction is known as Hoffmann degradation of amides.
CH3CH2CONH2+Br2+4KOHCH3CH2NH2+2KBr+K2CO3+2H2O

In the second reaction, amine reacts with nitrous acid to form primary alcohol.
CH3CH2NH2+HNO2NaNO2+HCl−−−−−−−273278KCH3CH2CH2OH+H2O+N2
Thus, A and B are Br2/KOH,HNO2 respectively.

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