CH3-CH3CH-CH2-CH3 N isomeric products C5H11Cl Misomeric productsWhat are N and M N and M are number of products formed -

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Preparation of Benzene and Homologues

CH3-CH3CH-CH2...

Question

$C H_{3} - (C H_{3}) C H - C H_{2} - C H_{3} C l_{2}, h v - --- \to N (isomeric products)$
$C5H11Clfractional distillation−−−−−−−−−−−−→M(isomeric products)$
What are N and M (N and M are number of products formed) ?

6, 6

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6, 4

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4, 4

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3, 3

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Solution

The correct option is B 6, 4
When 2-methyl butane is chlorinated in presence of sunlight, 6 monochlorinated products are obtained.
Thus N is 6.
On fractional distillation, 4 isomers are obtained.
Thus, M is 4.

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CH3−(CH3)CH−CH2−CH3Cl2, hv−−−−→N(isomeric products) C5H11Clfractional distillation−−−−−−−−−−−−→M(isomeric products)What are N and M (N and M are number of products formed) ?

The correct option is B 6, 4When 2-methyl butane is chlorinated in presence of sunlight, 6 monochlorinated products are obtained.Thus N is 6.On fractional distillation, 4 isomers are obtained.Thus, M is 4.

$C H_{3} - (C H_{3}) C H - C H_{2} - C H_{3} C l_{2}, h v - --- \to N (isomeric products)$
$C5H11Clfractional distillation−−−−−−−−−−−−→M(isomeric products)$
What are N and M (N and M are number of products formed) ?

The correct option is B 6, 4
When 2-methyl butane is chlorinated in presence of sunlight, 6 monochlorinated products are obtained.
Thus N is 6.
On fractional distillation, 4 isomers are obtained.
Thus, M is 4.