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B
CH3−CH2−O−CH2−CH3
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C
CH3−CH(CH3)−CH(CH3)−CH3
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D
CH3−CH2−CH3
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Solution
The correct option is ACH3−CH2−CH2−CH3 By this process, first alkyl halide forms which reduced by LiAlH4 to form alkane and again bromination takes place to give alkyl halide which in presence of Na/dryether forms alkane as product (Wurtz reaction).