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Question

CH3−CH3Br2/hv−−−−→ALiAlH4−−−−→BBr2/hv−−−−→CNa/ether−−−−−→D

The compound D is:

A
CH3CH2CH2CH3
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B
CH3CH2OCH2CH3
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C
CH3CH(CH3)CH(CH3)CH3
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D
CH3CH2CH3
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Solution

The correct option is A CH3CH2CH2CH3
By this process, first alkyl halide forms which reduced by LiAlH4 to form alkane and again bromination takes place to give alkyl halide which in presence of Na/dryether forms alkane as product (Wurtz reaction).

CH3CH3Br2/hv−−−CH3CH2BrLiAlH4−−−CH3CH3Br2/hv−−−CH3CH2BrNa/dryether−−−−−−−CH3CH2CH2CH3

Option A is correct.

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