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Hydroboration Oxidation

CH 3- CH = CH...

Question

$C H_{3} - C H = C H_{2} H c l - - \to X a l c K O H - ---- \to Y H c l - ---- \to p e r o x i d e Z$ false statement is

A

X and Z are not same compounds

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B

Z in presence of Na / dry ether gives n - butane

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C

Y is propene

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D

Formation of 'X' follows Markownikoff's rule

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Solution

The correct option is B
Z in presence of Na / dry ether gives n - butane

X = isopropyl chloride Y = propene Z = propyl chloride

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