CH 3 -CH-CH-CH-CH- CH 3 O 3 - H 2 -Zn X-Y In the above reaction X Y are -

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CH 3 -CH=CH-C...

Question

${C H}_{3} - C H = C H - C H = C H - {C H}_{3} O_{3} / H_{2} / Z n - ------- \to X + Y$

In the above reaction X & Y are :

ethanal, propanone

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ethanal, ethandial

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propanone, ethandial

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ethanal, ethanal

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C H_{3} - C H_{2} - C H = C H - C H_{3} + H C l \to X + Y

C H_{3} - \oplus C H - C H_{3}

C H_{3} - \oplus C H - O C H_{3}

C H_{3} - \oplus C H - C O C H_{3}

I . ⊖ C H_{2} - \oplus C H - C H = C H - O - C H_{3}

I I . ⊖ C H_{2} - C H = C H - \oplus C H - O - C H_{3}

I I I . C H_{2} = C H - ⊖ C H - \oplus C H - O - C H_{3}

I V . C H_{2} = C H - ⊖ C H - C H = \oplus O - C H_{3}

C H_{2} = C H - C H = C H - O - C H_{3}

H_{2} = C H - C | C H_{3} H - C | C_{2} H_{5} H - C | O H H - C H_{3}

C H_{3} C H_{2} C H (C H_{3}) O C H_{2} C H_{3} H C l - - \to △ [X] + [Y]

[X]

[Y]

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