Question

${CH}_3-CH\left(Cl\right)-C_2{H}_5\underset{}{\overset{Alc.KOH}{\to }}{CH}_3-CH=CH-{CH}_3$
The above reaction proceeds via $E_{1}cb$ mechanism?

• A. It is second order and bumolecular
• B. It is first order and unimolecular
• C. It is first order an bimolecular
• D. It is second order and unimolecular

Answer 1

Answer: (D)

It is second order and unimolecular

The given reaction (dehydrochlorination of $2$-chlorobutane in presence of alcoholic $KOH$ to form $2$-butene) proceeds via $E_{1}cb$ mechanism.

$E_1$ = unimolecular elimination ;cB = conjugate base.
It is second order and unimolecular.