CH 3- CH I 2 KCN - H 2 O - H - -The end product will be-A- 2-cyanopropionic acidB- 2-methylethanoic acidC- Ethane-1-1-dicarboxylic acidD- Propionic acid

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Hydrolysis of Cyanides

CH 3- CH I 2 ...

Question

$C H_{3} - C H I_{2} K C N - -- \to H_{2} O / H^{+} - ---- \to Δ ?$
The end product will be:

2-cyanopropionic acid

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Ethane-1,1-dicarboxylic acid

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2-methylethanoic acid

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Propionic acid

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Solution

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Similar questions

C H_{3} - C H_{2} B r K O H - -- \to (alc.) (A) B r_{2} - -- \to C C l_{4} (B) 2 K C N - --- \to (C)

(C) H_{3} O^{+} - -- \to (D)

$H_{2} C O_{3}$ is called as ___________ acid

B r_{2} / H_{2} O

H_{2}

S_{2} O_{7}

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