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Byju's Answer
Standard XII
Chemistry
Van't Hoff Factor
CH3COOH dimer...
Question
C
H
3
C
O
O
H
dimerizes in benzene when
1.65
g
of
C
H
3
C
O
O
H
dissolved in
100
g
of benzene the elevation of
B
p
s
of the solution was found
0.36
K
. If
K
b
for benzene in
2.85
K
.
k
g
l
m
o
l
. Then find Vant Hoff factor and degree of association of
C
H
3
C
O
O
H
.
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Solution
Δ
7
b
=
K
b
×
W
M
×
W
×
i
⇒
0.36
=
2.85
×
1.65
×
1000
60
×
100
×
i
∴
i
=
V
a
n
′
t
H
o
f
f
f
a
c
t
o
r
=
0.46
C
H
3
C
O
O
H
1
−
α
⇌
(
C
H
3
C
O
O
H
)
2
α
2
∴
i
=
1
+
α
2
∴
α
=
0.275
=
27.5
%= Degree of association
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0
Similar questions
Q.
Assuming complete association, van't Hoff factor for
C
H
3
C
O
O
H
in benzene is:
Q.
What is the value of van’t Hoff factor (i) for
60
%
association of
C
H
3
C
O
O
H
in benzene?
Q.
If '
α
' is degree of dimerisation of
C
H
3
C
O
O
H
in benzene, then van't Hoff factor '
i
' for circulation of colligative properties is:
Q.
Predict whether van't HOff factor
(
i
)
is less than one or greater than one in the following:
(i)
C
H
3
C
O
O
H
dissolved in water
(ii)
C
H
3
C
O
O
H
dissolved in benzene
Q.
One molal solution of a carboxylic acid in benzene shows the elevation boliling point of 1.518 K. The degree of association for dimerization of the acid in benzene is
(
k
b
for benzene= 2.53 K kg
m
o
l
−
1
)
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