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Question

CH3COOH Br2/P−−−−→Y(i)KCN−−−−−→(ii)H3O+X
Here, X is:

A
glycollic acid
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B
hydroxy propionic acid
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C
succinic acid
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D
malonic acid
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Solution

The correct option is D malonic acid
When acetic acid undergoes bromination,
CH3COOHBr2/P−−−BrCH2COOH

Further with KCN gives,
BrCH2COOHKCN(alc.)−−−−−NCCH2COOH

Finally,
NCCH2COOHKCN(alc.)−−−−−HOOCCH2COOH Which is malonic acid.

Option D is correct.


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