CH3COOH A B C -Then C is-

The correct option is B mustard gas CH_3COOH C_2H_5OH C_2H_4 2C_2H_4 + S_2Cl_2 ⟶ Cl CH_2 CH_2 S CH_2 CH_2 Cl Thus we get mustard gas as a product. ...

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Byju's Answer

Standard XII

Chemistry

Bleaching Powder

CH3COOH A B C...

Question

$C H_{3} C O O H L i A I H_{4} - ---- \to A H_{2} S O_{4} - --- \to 170^{0} C B S_{2} C l_{2} - -- \to C$ .Then $C$ is:

tear gas

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mustard gas

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cooking gas

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water gas

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Solution

The correct option is B mustard gas
$C H_{3} C O O H L i A l H_{4} - --- \to C_{2} H_{5} O H H_{2} S O_{4} - --- \to C_{2} H_{4}$

$2 C_{2} H_{4} + S_{2} C l_{2} ⟶ C l - C H_{2} - C H_{2} - S - C H_{2} - C H_{2} - C l$

Thus we get mustard gas as a product.

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Similar questions

{C H}_{3} C O O H C a {(O H)}_{2} - ---- \to A C a {(O O C H)}_{2} - ------- \to Δ B {N H}_{2} O H - ---- \to C

Identify

C

in the given series.

Q. In the reaction,

C H_{3} C O O H L i A l H_{4} - --- \to A P C l_{5} - -- \to B A l c . K O H - ----- \to C,

the product

C

is:

Q. The end product

^{'} C^{'}

in the following sequence of chemical reactions is:

C H_{3} C O O H C a C O_{3} - --- \to A H e a t - -- \to B N H_{2} O H - ---- \to C

{C H}_{3} C O O H C a {C O}_{3} - --- \to A H e a t - -- \to B {N H}_{2} O H - ---- \to C

The end product of reaction is:

Q. Name the end product in the following series of reactions.

C H_{3} C O O H N H_{3} - -- \to A Δ - \to B P_{2} O_{5} - -- \to C

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CH3COOHLiAIH4−−−−−→AH2SO4−−−−→1700CBS2Cl2−−−→C .Then C is:

The correct option is B mustard gasCH3COOHLiAlH4−−−−→C2H5OHH2SO4−−−−→C2H42C2H4+S2Cl2⟶Cl−CH2−CH2−S−CH2−CH2−ClThus we get mustard gas as a product.

$C H_{3} C O O H L i A I H_{4} - ---- \to A H_{2} S O_{4} - --- \to 170^{0} C B S_{2} C l_{2} - -- \to C$ .Then $C$ is:

The correct option is B mustard gas
$C H_{3} C O O H L i A l H_{4} - --- \to C_{2} H_{5} O H H_{2} S O_{4} - --- \to C_{2} H_{4}$

$2 C_{2} H_{4} + S_{2} C l_{2} ⟶ C l - C H_{2} - C H_{2} - S - C H_{2} - C H_{2} - C l$

Thus we get mustard gas as a product.