$C H_{3} C O O N a$ on reaction with $C H_{3} C O C l$ gives :

acetic anhydride

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methyl acetate

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acetyl chloride

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acetone

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Solution

The correct option is A acetic anhydride
a molecule of NaCl is formed with the formation of acetic anhydride ( $C H_{3} C O O C O C H_{3}$ ), the reaction is:

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H g S O_{4} + H_{2} S O_{4}

C H_{2} = C H_{2} + C H_{3} C O C l A l C l_{3} - -- \to

H g S O_{4} + H_{2} S O_{4}

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