$C H_{3} - H_{3} C - C H_{3} C l_{2}, h v \to N$ (isomeric products) $C_{5} H_{11} C l F r a c t i o n a l d i s t i l l a t i o n \to M$ (isomeric products). What are N and M?

6, 6

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6, 4

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4, 4

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3, 3

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Solution

The correct option is B $6, 4$
$C H_{3} - C H_{2} - C H_{3} C l_{2}, h v - --- \to C_{5} H_{11} C l F . D - - \to M$
$A$ $B$ $C$
$\Rightarrow 6$ isomers of $B$ are possible.
After fractional distillation we can collect $4$ isomers of C
$∴ 6, 4$ .

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(B)

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