${C H}_{3} - I + 2 N a + I - {C H}_{3} d r y e t h e r - ---- \to$ _______

C_{2} H_{5} - C_{2} H_{5}

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{C H}_{4}

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C_{3} H_{8}

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{C H}_{3} - {C H}_{3}

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Solution

The correct option is D ${C H}_{3} - {C H}_{3}$
When methyl Iodide is treated with sodium in the presence of dry ether, Ethane is formed .It is
called Wurtz reaction.
Dry ether
$C H_{3} - I + 2 N a + I - C H_{3} \to C H_{3} - C H_{3} + 2 N a I$
So option $D$ is correct

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