$C H_{3} - O | | C - H H C N \to (A) H_{3} O^{\oplus} \to (B) \to Δ (C) L i A l H_{4} \to (D) H I O_{4} \to H C H O + (E)$
Compound (C) can show geometrical isomerism. Product (E) of the reaction will be.

C H_{3} - O | | C - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H_{2} - O | | C - H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C H O

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

HCHO

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $C H_{3} - C H O$

Suggest Corrections

Similar questions

{C H}_{3} - {C H}_{2} - O ∥ C - {C H}_{2} - {C H}_{2} - {C H}_{3}

{C H}_{3} - O ∥ C - {C H}_{3} | C | {C H}_{3} - {C H}_{3}

C H_{3} - C H_{2} - C H O

C H_{3} - C | | O - C H_{3}

C H_{3} - O | | C - C H_{3} (A), C H_{3} - O | | C - H (B), C H_{3} - O | | C - C H_{2} - C l (C), H - O | | C - H (D), C l - C H_{2} - O | | C - H (E)

C H_{3} - C H_{3} | C = O

C H_{2} = P P h_{3} D M S O - --- \to C H_{3} - C H_{3} | C = C H_{2} + P h_{3} P = O

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

Join BYJU'S Learning Program