$C H_{3} - O H | C = C H - C H_{2} - C O O H$
The IUPAC name of the above given compound is:

hydroxypentenoic acid

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4-Hydroxy-3-pentenoic acid

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4-hydroxy-4-pentenoic acid

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3-hydroxy-4-methyl-3-enepentenoic acid

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Solution

The correct option is B 4-Hydroxy-3-pentenoic acid
Two functional groups are present in the given compound. Priority will be given to $- C O O H$ group. The numbering will start from carboxylic acid carbon. Double bond will get number 3 and hydroxy group will get number 4.
Hence, the IUPAC name is 4-hydroxy-3-pentenoic acid.

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Similar questions

C H_{2} - C H - C O O H ∣ ∣ O H N H_{2}

The Correct IUPAC name of the following compound is $H O O C - C H_{2} - C O O H | C | O H - C H_{2} - C O O H$

The IUPAC name of CH₂=CHCHOH-CH₂CHO is:

3-ethynyl-2-hydroxy-4-methylhex-3-en-5-ynoic

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