$C H_{3} - O H | C H - C H_{2} - C H_{2} - O H C r O_{3} ⟶ P y r i d i n e c o l d P r o d u c t$
What is the major product of the following reaction ?

C H_{3} - O H | C H - C H_{2} - O | | C - H

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C H_{3} - O | | C - C H_{2} - O | | C - H

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C H_{3} - O | | C - C H_{2} - O | | C - O H

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C H_{3} - O H | C H - C H_{2} - O | | C - O H

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Solution

The correct option is B $C H_{3} - O | | C - C H_{2} - O | | C - H$

Primary alcohols are oxidized to aldehydes and secondary alcohols are oxidized to ketones by $C r O_{3} / H_{2} S O_{4}$ or Pyridine
So, (Refer to Image)

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Similar questions

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

C H_{3} - C H_{3} | C H - O | | C - C H_{2} - O H | C H_{2}

C H_{3} - C H = C H - C H_{2} - O | | C - C H_{3} \to C H_{3} - C H = C H - C H_{2} - O | | C - O H

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