Question

$C{H}_3\underset{\left(aq\right)}{COO{C}_2{H}_5}+\underset{\left(aq\right)}{NaOH}⟶\underset{\left(aq\right)}{C{H}_{3}COONa}+\underset{\left(aq\right)}{C_2{H}_{5}OH}$

Which one of the following statements is correct for the reaction?

• A. Order is two but molecularity is one
• B. Order is one but molecularity is two
• C. Order is one and molecularity is one
• D. Order is two and molecularity is two

Answer 1

Answer: (D)

Order is two and molecularity is two

Assuming reaction to be elementary since nothing is given about the concentration.

$C{H}_{3}COO{C}_2{H}_5+NaOH\to C{H}_{3}COONa+C_2{H}_{5}OH$

is a bimolecular reaction since 2 reactants molecules are involved in the reaction. It is a second-order reaction as the reaction is elementary.

Rate, $r=k\left[C{H}_{3}COO{C}_2{H}_5\right]\left[NaOH\right]$

Order, $n=1+1=2$