CH3-CH3-CH-O-C-C6H5-X- Major product -X- will be-

The correct option is A CH_3 CH_3|CH O O||C C_6H_5 This is #160;Baeyer Villiger oxidation.MCPBA is used to provide one extra oxygen atom, the mechanism ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Intramolecular Aldol Condensation

CH3-CH3|CH-O|...

Question

$C H_{3} - C | C H_{3} H - O | | C - C_{6} H_{5} M C P B A - ---- \to [X]$
Major product [X] will be:

C H_{3} - C | C H_{3} H - O | | C - O C_{6} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} - C | C H_{3} H - O - O | | C - C_{6} H_{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} - C H_{2} - O - O | | C - C H_{2} - C_{6} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} - C H_{2} - O - O | | C - C H_{2} - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C H_{3} - C | C H_{3} H - O - O | | C - C_{6} H_{5}$

This is Baeyer Villiger oxidation.

MCPBA is used to provide one extra oxygen atom, the mechanism is like as shown.
Hence, an alkyl group with higher stability migrates.

Baeyer-Villiger oxidation is regioselective. Of the two alpha carbons in the ketone, the one that can stabilize a positive charge more effectively, which is the more highly substituted one, migrates from carbon to oxygen preferentially.

Migratory aptitude: hydrogen > tertiary alkyl > secondary alkyl > phenyl > primary alkyl > methyl

Hence, option $B$ is correct.

Suggest Corrections

Similar questions

Q. Which pair of the following carbonyl compounds can be differentiated by

I_{2} / N a O H

Q. The order of stability of the following tautomeric compounds is:

C H_{2} = O H | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} - O | | C - C H_{3} ⇌ C H_{3} - O H | C = C H - O | | C - C H_{3}

I

I I

I I I

C H_{2} = O H | C - C H_{2} (I) - O | | C - C H_{3} ⇌ C H_{3} - O | | C - C H_{2} (I I) - O | | C - C H_{3}

⇌ C H_{3} - O H | C = C H (I I I) - O | | C - C H_{3}

The order of stability of the following tautomeric compounds is:

Q. In the given reaction,

[X]

will be:

C H_{3} - C H | C H_{3} - O | | C - C H_{2} - C H_{3} C F_{3} C O O O H - ------- \to [X]

major product

i) C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - O = C H_{2} - C H_{3}

i i) C H_{3} - C H_{2} - C H_{2} - O - C H_{3} | C | C H_{3} - C H_{3}

Give the major products that are formed by heating each of the following ethers with HI.

Join BYJU'S Learning Program

CH3−C|CH3H−O||C−C6H5MCPBA−−−−−→[X] Major product [X] will be:

$C H_{3} - C | C H_{3} H - O | | C - C_{6} H_{5} M C P B A - ---- \to [X]$
Major product [X] will be: