$C H_{3} - C H_{3} | C | - C H_{3} C H_{2} - C H_{3} | C H - C H_{3}$ $B r_{2} / h u - --- \to$

For the given reaction how many products are optically active (all isomers) :

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 4
Optimally active isomers are-
$1 - C h l o r o - 2, 2, 4 - t r i m e t h y l p e n t a n e$
$2 - C h l o r o - 2, 2, 4 - t r i m e t h y l p e n t a n e$
$3 - C h l o r o - 2, 2, 4 - t r i m e t h y l p e n t a n e$
$4 - C h l o r o - 2, 2, 4 - t r i m e t h y l p e n t a n e$

Suggest Corrections

Similar questions

C H_{3} - O H | C H - C O O H Δ - \to

C H_{3} - C H_{2} - C H_{2} - C H_{3}

C H_{3} - C H = C H - C H_{3}

{C H}_{3} - B r | C | H - C H_{2} - C H_{3} + a l c . K O H \to X

{C H}_{3} - C H | C H_{3} - C H = C H_{2} O_{3} - \to Y + Z

{CH}_{3} - {CH}_{2} - CH = {CH}_{3}

C H_{3} - C H_{3}, C H_{2} = C H_{2}

C H \equiv C H

Join BYJU'S Learning Program