Question

$C{H}_3-\underset{OH}{\underset{|}{,CH}}-C{H}_2-C{H}_3\stackrel{Conc.H_{2}S{O}_4}{\to }Product\left(I\right)+Product\left(II\right)$

What is not true regarding the products?

• A. Product-$I$ and $II$ are position isomers
• B. product-I and II contains the same number of $s{p}^3$ and $s{p}^2$ carbon atoms
• C. The yield of the product $I$ and $II$ is same
• D. Reaction obeys Saytzeff rule

Answer 1

Answer: (C)

The yield of the product $I$ and $II$ is same

When you dehydrate an alcohol, you remove the -OH group, and a hydrogen atom from the next carbon atom in the chain. With molecules like butan-2-ol, there are two possibilities when that happens.

(Refer image)

Dehydration of butan-2-ol leads to a mixture containing:

• but-1-ene

• cis-but-2-ene (also known as (Z)-but-2-ene)

• trans-but-2-ene (also known as (E)-but-2-ene)

• * Alcohols undergo dehydration (loss of water molecule) in acidic medium to give olefins. A double bond is formed due to loss of water molecule. It is an elimination reaction. According to Saytzeff's rule (also Zaitsev's rule), during dehydration, more substituted alkene (olefin) is formed as a major product, since greater the substitution of double bond greater is the stability of alkene.
  

• Option C is wrong