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Nucleophile

CH3Br+Nu⊖→ CH...

Question

$C H_{3} B r + N u^{⊖} \to C H_{3} - N u + B r$ decreasing order of the rate of above reaction with nucleophiles $(N u^{⊖})$ $A$ to $D$ is: $[N u^{⊖} = (A) P h O^{-}, (B) A c O^{-}, (C) H O^{-}, (D) C H_{3} O^{-}]$

C > D > A > B

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D > C > B > A

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A > B > C > D

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B > D > C > A

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Solution

The correct option is B $C > D > A > B$
Acidic character: $A c O H > P h O H > M e O H > H_{2} O$
$p K_{a}$ value respectively : $4.75, 9.9, 15.5, 15.74$

Basic and nucleophilic characters are same because of same nucleophilic centre.
Nucleophilic order: $A c O^{⊖} < P h O^{⊖} < M e O^{⊖} <^{⊖} O H$

Answer : $(B) < (A) < (D) < (C)$ : Option (A)

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Similar questions

{C H}_{3} - B r + {N u}^{⊖} ⟶ {C H}_{3} - N u + B r

({N u}^{⊖}) (A)

(D)

[{N u}^{⊖} \Rightarrow (A) P h O^{⊖} (B) A C O^{⊖} (C) ⊖ O H (D) {C H}_{3} O^{⊖}

C H_{3} B r + N u^{-} \to C H_{3} - N u + B r^{-}

(N u^{-})

A

D

P h O^{-}

A c O^{-}

H O^{-}

C H_{3} C H_{2} O^{-}

d = λ (a \times b) + μ (b \times c) + ν (c \times a)

[a b c] = \frac{1}{8}

λ + μ + ν

C H_{3} C | O | - O^{-}

C H_{3} O^{-}

C N^{-}

H B r

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