$C H_{3} C H_{2} C H_{2} C H_{3} C l_{2} - - \to h v A + B$ (monochlorination products) The approximate ratio of percentage yields of A and B formed in the above reaction is ?

50 : 50

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38 : 15

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45 : 55

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60 : 40

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Solution

The correct option is A $38 : 15$
Since relative reactivity towards $1^{o}, 2^{o}, 3^{o}$ atoms are not given, We are taking it as default $1 : 3.8 (1^{o} : 2^{o})$
Relative Probability (RP) $=$ No. of hydrogen $\times$ Relative reactivity
$1^{o} H^{'} s$
$R P = 6 \times 1 = 6$ (Product B)
$2^{o} H^{'} s$
$R P = 4 \times 3.8 = 15.2$ (Product A)
Ratio $= \frac{15.2 / 21.2}{6 / 21.2} = \frac{15.2}{6} = \frac{152}{60} = 38 : 15$

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