CH3CH2Cl X Y Z- Z in the above reaction is-

The correct option is A CH_3CH_2CH_2NHCOCH_3 #160; CH_3CH_2Cl (X)CH_3CH_2CN(Y)CH_3CH_2CH_2NH_2(Z)CH_3CH_2CH_2NHCOCH_3 ...

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Synthesis by Reduction of Nitriles

CH3CH2Cl X Y ...

Question

$C H_{3} C H_{2} C l N a C N - --- \to X N i / H_{2} - --- \to Y A c e t i c - ----- \to a n h y d r i d e Z$ . $Z$ in the above reaction is:

C H_{3} C H_{2} C H_{2} N H C O C H_{3}

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C H_{3} C H_{2} C H_{2} N H_{2}

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C H_{3} C H_{2} C H_{2} C O N H C H_{3}

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C H_{3} C H_{2} C H_{2} C O N H C O C H_{3}

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Solution

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C H_{3} C H_{2} C l N a C N - --- \to X N i / H_{2} - --- \to Y a c e t i c a n h y d r i d e - --------- \to Z

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C H_{3} C H_{2} C l N a C N - --- \to X N i / H_{2} - --- \to Y Acetic Anhydride - --------- \to Z

C H_{3} C H_{2} C l N a C N - ----- \to

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N i / H_{2} - ---- \to

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A c e t i c a n h y d r i d e - ------------- \to

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Z

C H_{2} = C H C H_{2} N H_{2},

C H_{3} C H_{2} C H_{2} N H_{2},

C H \equiv C C H_{2} N H_{2}

Z

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