$C H_{3} C H_{2} O H$ can be converted into $C H_{3} C H O$ by . . . .
(a) catalytic hydrogenation
(b) treatment with $L i A I H_{4}$
(c) treatment with pyridinium chlorochromate
(d) treatment with $K M n O_{4}$

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Solution

Ethanal $(C H_{3} C H O)$ is an oxidised product of ethanol. Pyridinium chlorochromate $(C_{5} H_{5} + N H C l - C r O_{3})$ oxidises primary alcohols to aldehydes. Strong oxidising agents such as $K M n O_{4}$ are used for getting carboxylic acid from alcohols.
The oxidation process can be stopped at the aldehyde stage if Cr(VI) reagents such as Collin's reagent $(C r O_{3} . 2 C_{5} H_{5} N)$ , Corey's reagent or pyridinium chlorochromate and pyridinium dichromate $[(C_{5} H_{5} N H_{2})^{2 +} C r_{2} O_{7}^{2 -}]$ in anhydrous medium are used as the oxidising agent. So, the correct option is (c).
$C H_{3} C H_{2} O H E t h a n o l P C C - -- \to C H_{3} C H O E t h a n o l$

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