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Hydroboration Oxidation

CH3CH2OH is c...

Question

$C H_{3} C H_{2} O H$ is converted into $C H_{3} C H O$ in the presence of:

N a_{2} C r_{2} O_{7}

and NaOH

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N a_{2} C r_{2} O_{7}

and

a q . H_{2} S O_{4}

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NaOH

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Fe in presence of NaOH

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Solution

The correct option is B $N a_{2} C r_{2} O_{7}$ and $a q . H_{2} S O_{4}$
Alcohols are oxidised to aldehydes by mixture of $N a_{2} C r_{2} O_{7}$ and $H_{2} S O_{4}$ . This mixture produces nascent oxygen.

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Similar questions

F e C r_{2} O_{4}

N a_{2} C r O_{4}

N a_{2} C r_{2} O_{7}

F e C r_{2} O_{4} + N a O H + a i r ⟶ (A) + F e_{2} O_{3}

(A) + (B) ⟶ N a_{2} C r_{2} O_{7}

N a_{2} C r_{2} O_{7} + X △ ⟶ C r_{2} O_{3}

C r_{2} O_{3} + Y △ ⟶ C r

CH3COCl+H2------->CH3CH2OH------->CH3CHO(in presence of pd,BaSO4 and quinoline).

Here quinoline acts as what?

a)+ve catalyst

b)catalyst poison

c)promoter

d)medium

C H_{3} C H_{2} O H

C H_{3} C H O

C H_{3} C H O

H C N

H_{2} N - O H

C H_{3} C H O

N a O H

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