Question

$C{H}_{3}Cl$ has more dipole moment than $C{H}_{3}F$ because:

• A. electron affinity of chlorine is greater than that of fluorine
• B. the charge separation is larger in $C{H}_{3}Cl$ compared to $C{H}_{3}F$
• C. the repulsion between the bond pairs and non-bonded pairs of electrons is greater in $C{H}_{3}Cl$ than $C{H}_{3}F$
• D. chlorine has higher electronegativity than fluorine

Answer 1

Answer: (B)

the charge separation is larger in $C{H}_{3}Cl$ compared to $C{H}_{3}F$

$C{H}_{3}Cl\left(1.94D\right)$ has more dipole moment than $C{H}_{3}F\left(1.82D\right)$, because the charge separation is larger in $C{H}_{3}Cl$ compared to $C{H}_{3}F$. This is due to greater $C-Cl$ bond length than $C-F$ bond length.