Question

$C{H}_{3}Cl\to C{H}_4$
Above conversion can be achieved by:

• A. $Zn$ / $H^{+}$
• B. $LiAl$$H_4$
• C. $Mg$ / (ether) then $H_{2}O$
• D. all of these

Answer 1

The correct option is D all of these

In reaction A and B, due to $H^{⊝}$ transfer $C{H}_{3}Cl$ gives $C{H}_4$ through nucleophilic substitution. In C, after reaction with $Mg$, $C{H}_{3}Cl$ forms $C{H}_{3}MgCl$ which forms $C{H}_4$ after proton transfer from $H_{2}O$ .