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Question

CH3COCH3(g)C2H6(g)+CO(g) ; The initial pressure of CH3COCH3 is 50 mm. At equilibrium the mole fraction of C2H6 is 1/5 then Kp will be:

A
3.333 mm
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B
4.166 mm
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C
8.333 mm
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D
16.666 mm
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Solution

The correct option is A 3.333 mm
Mole fraction=Number of moles substanceTotal number of moles
Mole fraction of C2H6=Mole fraction of CO=x1+x=15=0.2
x=0.25
Mole fraction of CH3COCH3=10.251+0.25=0.6
Total number of moles initially =1
Total initial pressure =50 mm
Total number of moles at equilibrium =1+x=1.25
Total pressure at equilibrium =Total initial pressure×Total number of moles at equilibriumTotal number of moles initially
P=50×1.251=62.5 mm
Partial pressure of gas=Total pressure×Mole fraction of gas
Kp=[pC2H6].[pCO][pCH3COCH3]

Kp=[62.5×0.2].[62.5×0.2]62.5×0.6mm
Kp=4.166 mm

1131005_1170201_ans_ba476a06e30544adaa85782d9823d00c.jpg

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