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Characteristics of Chemical Equilibrium

CH3COCH3g⇌ C2...

Question

$C H_{3} C O C H_{3} (g) ⇌ C_{2} H_{6} (g) + C O (g)$ ; The initial pressure of $C H_{3} C O C H_{3}$ is 50 mm. At equilibrium the mole fraction of $C_{2} H_{6}$ is 1/5 then $K_{p}$ will be:

A

3.333 m m

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B

4.166 m m

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C

8.333 m m

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D

16.666 m m

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Solution

The correct option is A $3.333 m m$
$Mole fraction=Number of moles substanceTotal number of moles$
$Mole fraction of C2H6=Mole fraction of CO=x1+x=15=0.2$
$x = 0.25$
$Mole fraction of CH3COCH3=1−0.251+0.25=0.6$
Total number of moles initially $= 1$
Total initial pressure $= 50 m m$
Total number of moles at equilibrium $= 1 + x = 1.25$
Total pressure at equilibrium $= \frac{T o t a l i n i t i a l p r e s s u r e \times T o t a l n u m b e r o f m o l e s a t e q u i l i b r i u m}{T o t a l n u m b e r o f m o l e s i n i t i a l l y}$
$P = \frac{50 \times 1.25}{1} = 62.5 m m$
$Partial pressure of gas=Total pressure×Mole fraction of gas$
$K_{p} = \frac{[p_{C_{2} H_{6}}] . [p_{C O}]}{[p_{C H_{3} C O C H_{3}}]}$

$K_{p} = \frac{[62.5 \times 0.2] . [62.5 \times 0.2]}{62.5 \times 0.6} m m$
$K_{p} = 4.166 m m$

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