$C H_{3} C O C l$ is used to detect the number of amino groups in organic compounds. When a saturated polyamino compound (containing only C, H and N as primary amine) of molecular mass 161 is completely acetylated, it gives a compound of molecular mass 371. Find the total number of atoms per molecule.

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Solution

When one $- N H_{2}$ group is acetylated, there is increase in mass by 42 units.
$161 + 42 n = 371 \Rightarrow n = 5$ , where n is the number of amino groups.
Let the formula of the compound be,
$C_{x} H_{2 x + 2 + 5} N_{5}$
$12 \times x + 2 \times x + 2 + 5 + 5 \times 14 = 161$
$x = 6$
So, the compound is $C_{6} H_{19} N_{5}$
Number of atoms per molecule = 6 + 19 + 5 = 30

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CH3COCl is used to detect the number of amino groups in organic compounds. When a saturated polyamino compound (containing only C, H and N as primary amine) of molecular mass 161 is completely acetylated, it gives a compound of molecular mass 371. Find the total number of atoms per molecule.

When one −NH2 group is acetylated, there is increase in mass by 42 units. 161+42n=371⇒n=5 , where n is the number of amino groups. Let the formula of the compound be, CxH2x+2+5N5 12×x+2×x+2+5+5×14=161 x=6 So, the compound is C6H19N5 Number of atoms per molecule = 6 + 19 + 5 = 30