CH3COONaABCD- Incorrect statement is

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Standard XI

Chemistry

Decarboxylation Reaction of Alkanes

CH3COONaABCD....

Question

$C H_{3} C O O N a N a O H - --- \to C a O A O n e m o l e - ---- \to C l_{2} / h v B N a - -- \to E t h e r C (C H_{3} C O O)_{2} M n - --------- \to D$ . Incorrect statement is

A and C are homologues

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Salt of D on Kolbe's electrolysis gives C

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C can exhibit conformational isomerism

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B on reduction with Zn / HCl gives methane

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Solution

The correct option is D
B on reduction with Zn / HCl gives methane

A is methane , B is $C H_{3} C l,$ C is $C_{2} H_{6}$ , D is $C H_{3} C O O H$

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$C H_{3} C O O N a N a O H - --- \to C a O A O n e m o l e - ---- \to C l_{2} / h v B N a - -- \to E t h e r C (C H_{3} C O O)_{2} M n - --------- \to D$ . Incorrect statement is

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CH3COONaNaOH−−−−→CaOAOne mole−−−−−→Cl2/hvBNa−−−→EtherC(CH3COO)2Mn−−−−−−−−−−→D. Incorrect statement is

The correct option is D B on reduction with Zn / HCl gives methane A is methane , B is CH3Cl, C is C2H6, D is CH3COOH

$C H_{3} C O O N a N a O H - --- \to C a O A O n e m o l e - ---- \to C l_{2} / h v B N a - -- \to E t h e r C (C H_{3} C O O)_{2} M n - --------- \to D$ . Incorrect statement is

The correct option is D
B on reduction with Zn / HCl gives methane

A is methane , B is $C H_{3} C l,$ C is $C_{2} H_{6}$ , D is $C H_{3} C O O H$