MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Decarboxylation Reaction of Alkanes

CH 3 COON a N...

Question

$C H_{3} C O O N a N a O H - --- \to C a O A O n e m o l e - ---- \to C l_{2} / h v B N a - -- \to E t h e r C (C H_{3} C O O)_{2} M n - --------- \to D$ . Incorrect statement is

A

A and C are homologues

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

Salt of D on Kolbe's electrolysis gives C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

C can exhibit conformational isomerism

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

B on reduction with Zn / HCl gives methane

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
B on reduction with Zn / HCl gives methane

A is methane , B is $C H_{3} C l,$ C is $C_{2} H_{6}$ , D is $C H_{3} C O O H$

Suggest Corrections

thumbs-up

0

Similar questions

(A), (B)

(C)

are three non-cyclic functional isomers of a carbonyl compound with molecular formula

C_{4} H_{8} O

(A)

(C)

give positive Tollen's test whereas isomer

(B)

does not give Tollen's test but gives positive Iodoform test. Isomers

(A)

(B)

on reduction with

Z n (H g) / c o n c

H C l

give the same product

(D)

Write the structures of

(A), (B), (C)

(D)

.

Q. Electrolysis of aq.

C H_{3} C O O N a

(B)

(B)

when heated with

C l_{2}

400^{0} C

(C)

(C)

when reacts with excess of alcoholic

N H_{3}

(D)

. The final product

(D)

(A), (B)

(C)

are three non-cyclic functional isomers of a carbonyl compound with molecular formula

C_{4} H_{8} O

(A)

(C)

give positive Tollens' test whereas isomer

(B)

does not give Tollens' test but gives protection Iodoform test. Isomers

(A)

(B)

on reduction with

Z n (H g) / c o n c

H C l

give the same product

(D)

(A), (B)

(C)

isomers, which one is least reactive towards addition of

H C N

?

Q. An organic compound A on reduction gives compound B, which on reaction with trichloro methane and caustic potash forms C. The compound 'C' on catalytic reduction gives N-methyl benzenamine, the compound 'A' is :

Q. Base hydrolysis of an ester with NaOH gives a carboxylic acid whose sodium salt on Kolbe's electrolysis yields ethane. The ester is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Alkanes - Preparation

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Decarboxylation Reaction of Alkanes

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon