CH 4-2 O 2- CO 2-2 H 2 OInitially- 16 g of CH 4 is combusted in 22-4 L of O 2 at STP- Identify the correct statement-A- CH 4 is the limiting reagentB- O 2 is the limiting reagentC- CH 4 will be completely consumedD- 1 mole of CH 4 remain unreacted

The correct option is B O_2 is the limiting reagentCH_4 + 2O_2 → CO_2 + 2H_2O 1 mole of CH_4 requires 2 moles of O_2 for complete combustion. Molar mass of me ...

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Byju's Answer

Standard XII

Chemistry

Straight Chain Hydrocarbons

CH 4+2 O 2→ C...

Question

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
Initially, $16 g$ of $C H_{4}$ is combusted in $22.4 L$ of $O_{2}$ at STP. Identify the correct statement.

C H_{4}

is the limiting reagent

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O_{2}

is the limiting reagent

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C H_{4}

will be completely consumed

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1 mole of

C H_{4}

remain unreacted

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Solution

The correct option is B $O_{2}$ is the limiting reagent
$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$

1 mole of $C H_{4}$ requires 2 moles of $O_{2}$ for complete combustion.
Molar mass of methane = $16 g$ .
Number of moles of methane in $16 g$ sample = $\frac{16 g}{16 g}$ = $1 mol$ .

$1$ mole of all the gases occupy $22.4 L$ at STP.
Number of moles of oxygen $= 22.4 L = 1 mol (given)$

As only 1 mol of $O_{2}$ is available, $O_{2}$ acts as the limiting reagent in this reaction.

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Similar questions

C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O

Initially,

16 g

C H_{4}

is combusted in

22.4 L

O_{2}

at STP. Identify the correct statement.

Q. In the below given redox reaction,

C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O

The oxidising agent and substance being oxidised are:

Q. For the reaction,

2 H_{2} (g) + O_{2} (g) \to 2 H_{2} O (g)

Initially, 3 moles of

H_{2}

and 2 moles of

O_{2}

are present. Identify the correct statement.

Q. What volume of

O_{2}

is required to burn completely a mixture of

22.4 d m^{3}

C H_{4}

and

11.2 d m^{3}

H_{2}

?
The reactions are:

C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O

;

2 H_{2} + O_{2} \to 2 H_{2} O

(All volume at S.T.P).

Q. What mass of

C O_{2}

could be formed by the reaction of

16

: g

C H_{4}

with

48

g of

O_{2}

C H_{4} + 2 O_{2} ⟶ C O_{2} + 2 H_{2} O

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CH4+2O2→CO2+2H2O Initially, 16 g of CH4 is combusted in 22.4 L of O2 at STP. Identify the correct statement.

$C H_{4} + 2 O_{2} \to C O_{2} + 2 H_{2} O$
Initially, $16 g$ of $C H_{4}$ is combusted in $22.4 L$ of $O_{2}$ at STP. Identify the correct statement.