To obtain high yields of CH3Cl, the ratio of CH4 to Cl2 must be:
A
high
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B
low
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C
equal
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D
can't be predicted
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Solution
The correct option is D high CH4+Cl2hv−→CH3Cl+HCl
To obtain high yields of CH3Cl, the ratio of CH4 to Cl2 must be high, otherwise if we take low ratio of CH4 to Cl2 i.e. excess Cl2 has been used then there will be formation of more than mono substituted products i.e. CH2Cl2,CHCl3,CCl4