$C H_{4}, N H_{3}, H_{2} O, H F$
Find acidic order using $I$ effect.

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Solution

Fluorine is the most electronegative, so $F -$ (fluoride ion) is the least willing to donate electrons (the weakest base). Overall, the electronegativity order is $C (2.5) < N (3.0) < O (3.5) < F (4.0)$ ,
the order of basicity is $- C H_{3}$ (strongest base) $> - N H 2 > H O - > F -$

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