$C H \equiv C H + 2 C H_{3} C O O H \to A Δ \to B + C$ . 'B' can be obtained from (X) by hydration and 'C' can be obtained from (Y) by heating with $P_{2} O_{5}$ . Hence 'A' is :

C H_{2} = C H - O - O | | C C H_{3}

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C H_{3} - C H (O - O | | C C H_{3})_{2}

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C H_{3} C H_{2} C O O C H_{3}

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C H_{3} C O O C H_{2} C H_{3}

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Solution

The correct option is D $C H_{3} - C H (O - O | | C C H_{3})_{2}$
In this reaction, first ethylidine acetate(A) forms which on heating gives acetaldehyde (B) and acetic anhydride (C).
Reaction of formation of ethylidine acetate:

$H - C = C - H A c e t y l e n e C H_{3} C O O H - ------ \to H g^{2 +} H_{2} C = C H - (O C O C H_{3}) C H_{3} C O O H - ------ \to H g^{2 +} C H_{3} - C H (O C O C H_{3})_{2}$
Ethylidine acetate

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Similar questions

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

P h - C H = C H - O | | C - C H_{3} \to P h - C H = C H - C O_{2} H

2 C H_{3} C H O O H^{⊖} - -- \to A △ - \to B;

C = C

C H_{2} = C H - . . N H - C H_{3}

C H_{2} = C H - . . O . . - C H_{3}

C H_{2} = C H - . . O . . - C H = C H_{2}

C H_{2} = C H - N H_{2}

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