${({CH}_{3})}_{3} CBr + H_{2} O \to {({CH}_{3})}_{3} COH + HBr is an example of :$

elimination reaction

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free radical substitution

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nucleophilic substitution

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electrophilic substitution

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Solution

The correct option is C nucleophilic substitution
${({CH}_{3})}_{3} Br + H_{2} O \to {({CH}_{3})}_{3} C - OH + HBr$
Br is substituted by $- O H$ (nucleophile)
Thus, it is nucleophilic substitution reaction.

It is a $S_{N} 1$ reaction (unimolecular substitution reaction).

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Similar questions

{({C H}_{3})}_{3} C B r + H_{2} O ⟶ {({C H}_{3})}_{3} C O H + H B r

{(C H_{3})}_{3} C B r + H_{2} O \to {(C H_{3})}_{3} C O H + H B r

Following reaction, $(C H_{3})_{3} C B r + H_{2} O \to (C H_{3})_{3} C O H + H B r$ is an example of

C H_{3} C H_{2} C H_{2} C l + N a I a c e t o n e - --- \to h e a t

(C H_{3})_{3} C B r + K O H e t h a n o l - --- \to h e a t

C H_{3} C H (B r) C H_{2} C H_{3} + N a O H w a t e r - -- \to

(C H_{3})_{3} C B r + K O H e t h a n o l - --- \to h e a t

C_{6} H_{5} O N a + C_{2} H_{5} C l ⟶

C H_{3} C H_{2} C H_{2} O H + S O C l_{2} ⟶

C H_{3} C H_{2} C H = C H_{2} + H B r p e r o x i d e - ---- \to

C H_{3} C H = C (C H_{3})_{2} + H B r ⟶

C_{6} H_{6} + B r_{2} F e \to C_{6} H_{5} B r + H B r

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