Question

CH3CH2I that is 1-iodo-ethane++aqueous KOH ==? CH3CH2I that is 1-iodo-ethane++alcoholic KOH==?

Answer 1

$$\begin{gathered} \text{Hi,} \\ \text{Iodoethane in presence of aq. KOH gives ethanol} \\ {\text{CH}}_3{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{aq}\mathrm{KOH}}{\to }{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{OH} \\ \mathrm{Iodoethane}\mathrm{in}\mathrm{presence}\mathrm{of}alcoholic.\mathrm{KOH}\mathrm{gives}\mathrm{ethene} \\ {\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{I}\stackrel{\mathrm{alcoholic}\mathrm{KOH}}{\to }{\mathrm{H}}_2\mathrm{C}={\mathrm{CH}}_2 \\ \mathrm{Regards} \end{gathered}$$