Question

$C{H}_{3}CHO$ (g) gives $C{H}_4$(g) + CO (g)

Rate =k ${\left[C{H}_{3}CHO\right]}^{\frac{3}{2}}$ determine their order of reaction and the dimensions of the rate constant.

Answer 1

Step 1:

Given rate = $k{\left[C{H}_{3}CHO\right]}^{\frac{3}{2}}$

Therefore, order of reaction = $\frac{3}{2}$

$k=\frac{Rate}{{\left[C{H}_{3}CHO\right]}^{\frac{3}{2}}}$

Step 2:

Dimension of rate constant = $\frac{mol{L}^{-1}{s}^{-1}}{{\left(mol{L}^{-1}\right)}^{\frac{3}{2}}}$

$=\frac{mol{L}^{-1}{s}^{-1}}{{mol}^{\frac{3}{2}}{L}^{-\frac{3}{2}}}$

$=L^{\frac{1}{2}}{mol}^{-\frac{1}{2}}{s}^{-1}$