CH3COOHLiAlH4−−−−→AH+−−−→443KBBr2−−→Calc.−−−→KOHD

D is .

Methane

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Acetylene

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Alcohol

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Solution

The correct option is B Acetylene
$C H_{3} C O O H L i A l H_{4} - --- \to H_{3} C - C H_{2} - O H H^{+} - -- \to 443 K$

$H_{2} C = C H_{2} B r_{2} - -- \to C C l_{4} H_{2} C | B r - B r | C H_{2} a l c . - -- \to K O H H C \equiv C H Acetylene + 2 K B r + 2 H_{2} O$

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Similar questions

C H_{3} C O O H L i A l H_{4} - --- \to A H^{+} - -- \to 443 K B B r_{2} - - \to C a l c . - -- \to K O H D

∣ ∣ ∣ ∣ \begin{matrix} a h + b g & g & a b + c h b f + b a & f & h b + b c a f + b c & d & b g + f c \end{matrix} ∣ ∣ ∣ ∣ = ∣ ∣ ∣ ∣ \begin{matrix} a h + b g & a & h b f + b a & h & b a f + b c & g & f \end{matrix} ∣ ∣ ∣ ∣

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\frac{MA}{HA} = \frac{7}{5}

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A B C D

A H ⊥ D C, D C = 10 m, A H = 10 m

A B C D .

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