Chandrabhal adds first N natural numbers and finds the sum to be 1850. However, actually one number was added twice by mistake. Find the difference between N and that number.

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Solution

The correct option is A 40
Sum of 1st 60 numbers $= \frac{60 \times 61}{2} = 1830$
Therefore, the number that has been added twice = 1850 - 1830 = 20
Hence, N - 20 = 60 - 20 = 40.

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Chandrabhal adds first N natural numbers and finds the sum to be 1850. However, actually one number was added twice by mistake. Find the difference between N and that number.

The correct option is A 40Sum of 1st 60 numbers =60×612=1830 Therefore, the number that has been added twice = 1850 - 1830 = 20 Hence, N - 20 = 60 - 20 = 40.

The correct option is A 40
Sum of 1st 60 numbers $= \frac{60 \times 61}{2} = 1830$
Therefore, the number that has been added twice = 1850 - 1830 = 20
Hence, N - 20 = 60 - 20 = 40.