Chandrika invested ₹ 20,000 for a period from June 2015 to May 2017 at a rate of 12 % per annum at simple interest. The interest received by her is .

₹ 4,800

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₹ 5,000

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₹ 4,600

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Solution

The correct option is A ₹ 4,800
Given,
P = ₹ 20,000, R = 12%.
Time period is from June 2015 to May 2017
$\Rightarrow$ N = 2 years
We know that,
$Simple Interest, S I = \frac{P \times N \times R}{100}$
$S I = \frac{20000 \times 2 \times 12}{100}$
$= ₹ 4, 800$
Therefore, the interest received by Chandrika is $= ₹ 4, 800$

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Chandrika invested ₹ 20,000 for a period from June 2015 to May 2017 at a rate of 12 % per annum at simple interest. The interest received by her is .

The correct option is A ₹ 4,800Given, P = ₹ 20,000, R = 12%. Time period is from June 2015 to May 2017 ⇒N = 2 years We know that, Simple Interest, SI=P×N×R100 SI=20000×2×12100 =₹ 4,800 Therefore, the interest received by Chandrika is =₹ 4,800