Change each of the given temperature to the Celsius and Kelvin scales: $68^{\circ} F, 5^{\circ} F$ and $176^{\circ} F .$

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Solution

Following are the expressions for the required conversions.

$T_{C} = \frac{5}{9} (T_{F} - 32)$

$T_{K} = \frac{5}{9} (T_{F} + 459.67)$

Thus, putting in values,

$T_{C 1} = \frac{5}{9} (68 - 32) = 20^{o} C$

$T_{C 2} = \frac{5}{9} (5 - 32) = {- 15}^{o} C$

$T_{C 3} = \frac{5}{9} (176 - 32) = 80^{o} C$

$T_{K 1} = \frac{5}{9} (68 + 459.67) = 293 K$

$T_{K 2} = \frac{5}{9} (5 + 459.67) = 258 K$

$T_{K 3} = \frac{5}{9} (176 + 459.67) = 353 K$

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Similar questions

Q. Convert each of the following temperature in

^{\circ} F

to the celsius and kelvin scale

68^{\circ} F, 5^{\circ} F, 176^{\circ} F

Q. Convert

100^{o}

F in to Celsius and Kelvin scale of temperature.

A solution is to be kept between $68^{\circ} F$ and $77^{\circ} F$ . What is the range of temperature in degree Celsius (C) if the Celsius /Fahrenheit (F) convension formula is given by $F = \frac{9}{5} C + 32$ ?

Q. A solution is to be kept between

68^{o} F

and

77^{o} F

. What is the range in temperature in degree Celsius (C) if the Celsius / Fahrenheit (F) conversion formula is given by

F = \frac{9}{5} C + 32 ?

A solution is to be kept between 68°F and 77°F. What is the range in temperature in degree Celsius (C) if the Celsius/Fahrenheit (F) conversion formula is given by

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Change each of the given temperature to the Celsius and Kelvin scales: 68∘F,5∘F and 176∘F.

Following are the expressions for the required conversions.TC=59(TF−32)TK=59(TF+459.67)Thus, putting in values,TC1=59(68−32)=20oCTC2=59(5−32)=−15oCTC3=59(176−32)=80oCTK1=59(68+459.67)=293KTK2=59(5+459.67)=258KTK3=59(176+459.67)=353K

Change each of the given temperature to the Celsius and Kelvin scales: $68^{\circ} F, 5^{\circ} F$ and $176^{\circ} F .$