Change in oxidation number is maximum in which of the following reaction?

C u + 4 H N O_{3} \to C u (N O_{3})_{2} + 2 N O_{2} + 2 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} S + 4 F_{2} \to 2 H F + S F_{6}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C l_{2} + 6 K O H \to 5 K C l + K C l O_{3} + 3 H_{2} O

No worries! We‘ve got your back. Try BYJU‘S free classes today!

K C l O_{3} + H_{2} O + F_{2} \to K C l O_{4} + 2 H F

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H_{2} S + 4 F_{2} \to 2 H F + S F_{6}$
In the reaction, $H_{2} S + 4 F_{2} \to 2 H F + S F_{6}$ ,

the oxidation state of sulphur changes from $- 2$ in $H_{2} S$ to $+ 6$ in $S F_{6}$ .

Thus, the change in oxidation number is $8$ . This change is maximum as compared to all the given reactions.

Option B is correct.

Suggest Corrections

Similar questions

A : 2 C_{6} H_{5} C H O + K O H ⟶ C_{6} H_{5} C O O K + C_{6} H_{5} {C H}_{2} O H

B : 3 {C l}_{2} + 6 K O H ⟶ 5 K C l + K C l O_{3} + 3 H_{2} O

C u + 4 H N O_{3} \to C u (N O_{3})_{2} + 2 H_{2} O + 2 N O_{2} (g)

△ G_{f}^{0}

^{- 1}

H I (g)

^{- 1}

H_{2} + I_{2} \to 2 H I

\to H_{2} + I_{2}

H_{2} + F_{2} \to 2 H F

2 H F \to H_{2} + F_{2}

C l_{2} + K O H \to K C l O_{3} + K C l + H_{2} O

X e F_{2} + B r O_{3}^{-} + H_{2} O ⟶ B r O_{4}^{-} + X e + 2 H F

Join BYJU'S Learning Program