Change the following celsius temperature to kelvin scale. (i) – 273°C (ii) – 100°C (iii) – 40°C (iv) + 30°C
In the Kelvin scale:
(i) – 273°C + 273 = 0 K
(ii) – 100°C + 273 = 173 K
(iii) – 40°C + 273 = 233 K
(iv) + 30°C + 273 = 303 K
Change the following celsius temperature to kelvin scale [2 MARKS] (i) – 273°C (ii) – 100°C (iii) – 40°C (iv) + 30°C
If A = {1, 2, 3}, B = {3, 4} and C = {4, 5, 6}, find
(i) A×(B∩C)
(ii) (A×B)∩(A×C)
(iii) A×(B∪C)
(iv) (A×B)∪(A×C)