Change the following from exponential form to logarithmic form-i 3 4 -81ii 6 -4 - 1 1296iii 1 81 3 - 4 - 1 27iv 216 1 - 3 -6v 13 -1 - 1 - 13

(i) 3 ^ 4 =81⟹log _ 3 81 =4 (ii) 6 ^ 4 = 1 1296 ⟹log _ 6 ( 1 1296 #160;) #160; = 4 (iii) ( 1 81 #160;) #160;^ 3 / 4 #160;= ...

376

You visited us 376 times! Enjoying our articles? Unlock Full Access!

Logarithms

Change the fo...

Question

Change the following from exponential form to logarithmic form.
(i) $3^{4} = 81$
(ii) $6^{- 4} = \frac{1}{1296}$
(iii) ${(\frac{1}{81})}^{\frac{3}{4}} = \frac{1}{27}$
(iv) ${(216)}^{\frac{1}{3}} = 6$
(v) ${(13)}^{- 1} = \frac{1}{13}$

Open in App

Solution

Suggest Corrections

Similar questions

{log}_{4} 64 = 3

{log}_{16} 2 = \frac{1}{4}

{log}_{5} (\frac{1}{25}) = - 2

{log}_{10} 0.1 = - 1

\{{(\frac{1}{3})}^{- 3} - {(\frac{1}{2})}^{- 3}\} \div {(\frac{1}{4})}^{- 3}

(3^{2} - 2^{2}) \times {(\frac{2}{3})}^{- 3}

{\{{(\frac{1}{2})}^{- 1} \times (- 4)^{- 1}\}}^{- 1}

{[{\{{(\frac{- 1}{4})}^{2}\}}^{- 2}]}^{- 1}

{\{{(\frac{2}{3})}^{2}\}}^{3} \times {(\frac{1}{3})}^{- 4} \times 3^{- 1} \times 6^{- 1}

{\{4^{- 1} \times 3^{- 1}\}}^{2}

{\{5^{- 1} \div 6^{- 1}\}}^{3}

{(2^{- 1} + 3^{- 1})}^{- 1}

{\{3^{- 1} \times 4^{- 1}\}}^{- 1} \times 5^{- 1}

(4^{- 1} - 5^{- 1}) \div 3^{- 1}

{(\frac{1}{3})}^{- 1}

{(\frac{- 2}{3})}^{- 1}

{(4^{- 1} \times 3^{- 1})}^{2}

{(5^{- 1} \div 6^{- 1})}^{3}

{(2^{- 1} + 3^{- 1})}^{- 1}

{(3^{- 1} \times 4^{- 1})}^{- 1} \times 5^{- 1}

Join BYJU'S Learning Program